x^2-96x+100=0

Solution for x^2-96x+100=0 equation:

x^2-96x+100=0

a = 1; b = -96; c = +100;
Δ = b2-4ac
Δ = -962-4·1·100
Δ = 8816
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{8816}=\sqrt{16*551}=\sqrt{16}*\sqrt{551}=4\sqrt{551}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-96)-4\sqrt{551}}{2*1}=\frac{96-4\sqrt{551}}{2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-96)+4\sqrt{551}}{2*1}=\frac{96+4\sqrt{551}}{2}
$